JAMB 2011 Mathematics · Question 3

A binary operation ⊕\oplus om real numbers is defined by x ⊕\oplus y = xy + x + y for two real numbers x and y. Find the value of 3 ⊕\oplus - 23\frac{2}{3}.

Options

  1. A.- 12\frac{1}{2}
  2. B.13\frac{1}{3}
  3. C.-1
  4. D.2

Answer: B. 13\frac{1}{3}

Explanation written with AI and checked against the answer key

1. Analyze the Question

We are given a binary operation defined as x⊕y=xy+x+yx \oplus y = xy + x + y. We need to evaluate this operation for the specific values x=3x = 3 and y=−23y = -\frac{2}{3}.

2. Explain the Concept

A binary operation is simply a rule that tells you how to combine two numbers to get a third number. In this case, the rule is:

  • Multiply the two numbers (xyxy)
  • Add the first number (xx)
  • Add the second number (yy)

To solve this, we substitute the given values into the formula and follow the BODMAS rule (multiplication before addition).

3. Show the Solution

Given: x⊕y=xy+x+yx \oplus y = xy + x + y Substitute x=3x = 3 and y=−23y = -\frac{2}{3}:

3⊕(−23)=(3×−23)+3+(−23)3 \oplus (-\frac{2}{3}) = (3 \times -\frac{2}{3}) + 3 + (-\frac{2}{3})

Step 1: Perform the multiplication 3×(−23)=−23 \times (-\frac{2}{3}) = -2

Step 2: Substitute back into the expression −2+3−23-2 + 3 - \frac{2}{3}

Step 3: Simplify the addition (−2+3)−23(-2 + 3) - \frac{2}{3} =1−23= 1 - \frac{2}{3}

Step 4: Subtract the fraction To subtract, convert 11 to a fraction with a denominator of 33: 33−23=13\frac{3}{3} - \frac{2}{3} = \frac{1}{3}

4. Identify the Answer

Comparing our result to the given options: A. −12-\frac{1}{2} B. 13\frac{1}{3} C. −1-1 D. 22

The calculated value matches option B.

5. Tip

When dealing with binary operations involving fractions, always simplify the multiplication part first. It often results in a whole number that makes the subsequent addition or subtraction much easier to handle. Don't rush to find a common denominator until you have simplified the entire expression as much as possible!

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