JAMB 2024 Chemistry · Question 117

How many moles of CO2_2 are produced when ethanol is burnt with 6g of oxygen

Options

  1. A.0.125
  2. B.0.250
  3. C.0.375
  4. D.0.750

Answer: A. 0.125

Explanation written with AI and checked against the answer key

To solve this problem, we need to follow the stoichiometry of the combustion reaction of ethanol.

1. Analyze the Question

We are given the mass of oxygen (O2O_2) used to burn ethanol (C2H5OHC_2H_5OH) and asked to find the number of moles of carbon dioxide (CO2CO_2) produced.

2. Explain the Concept

First, we must write the balanced chemical equation for the complete combustion of ethanol:

C2H5OH+3O2→2CO2+3H2OC_2H_5OH + 3O_2 \rightarrow 2CO_2 + 3H_2O

From the balanced equation:

  • 3 moles of O2O_2 produce 2 moles of CO2CO_2.
3. Show the Solution

Step 1: Calculate the molar mass of O2O_2. The atomic mass of Oxygen (O) = 16.0 g/mol. Molar mass of O2=16.0×2=32.0 g/molO_2 = 16.0 \times 2 = 32.0 \text{ g/mol}.

Step 2: Calculate the number of moles of O2O_2 provided.

Moles=massmolar mass=6 g32 g/mol=0.1875 moles of O2\text{Moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{6 \text{ g}}{32 \text{ g/mol}} = 0.1875 \text{ moles of } O_2

Step 3: Use the mole ratio to find the moles of CO2CO_2. From the balanced equation, the ratio of O2O_2 to CO2CO_2 is 3:23:2.

moles of CO2moles of O2=23\frac{\text{moles of } CO_2}{\text{moles of } O_2} = \frac{2}{3}
moles of CO2=23×0.1875\text{moles of } CO_2 = \frac{2}{3} \times 0.1875
moles of CO2=2×0.0625=0.125 moles\text{moles of } CO_2 = 2 \times 0.0625 = 0.125 \text{ moles}
4. Identify the Answer

Comparing our result to the options provided, the correct value is 0.125.

125.

5. Exam Tip

Always ensure your chemical equation is balanced before performing stoichiometric calculations. A common mistake is to use the wrong mole ratio (e.g., using 1:11:1 instead of 3:23:2). If you are ever unsure about the coefficients, quickly re-check the number of atoms on both sides of the arrow!

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