WAEC 2023 Physics · Question 32

The most appropriate value of fuse for a kettle rated 220 V, 1.06 kW is

Options

  1. A.3A
  2. B.6A
  3. C.5A
  4. D.4A

Answer: C. 5A

Explanation written with AI and checked against the answer key

Analyze the question: We need a fuse rating for a kettle rated 220 V and 1.06 kW. The fuse must be slightly higher than the normal operating current, so the kettle works normally but the fuse blows if the current becomes too large.

Concept: Power P = IV, so the working current is I = P / V.

Solution:

  1. Convert the power to watts: 1.06 kW = 1060 W
  2. Calculate the current: I = 1060 / 220 ≈ 4.82 A
  3. Choose a fuse rating just above 4.82 A.

Checking the options:

  • A (3 A) is below the working current, so it would blow immediately.
  • D (4 A) is also below 4.82 A, so it would blow.
  • C (5 A) is just above 4.82 A, so it is suitable.
  • B (6 A) is safe, but it is not the closest rating above the working current, so it is less appropriate.

The most appropriate fuse is therefore 5 A, which is option C.

Exam tip: For fuse questions, always calculate I = P/V first, then pick the smallest fuse rating that is greater than that current. Never choose a fuse below the working current, and avoid ones far above it, because they give poor protection.

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