WAEC 2019 Physics · Question 22

An electron of mass 9.1 x 10 ^ -31 kg moves with a speed of 2.0 x 10 ^6 ms ^ -1 round the nucleus of an atom…

Question

An electron of mass 9.1 x 10−31^{-31} kg moves with a speed of 2.0 x 106^6 ms−1^{-1} round the nucleus of an atom in a Circular path of radius 6.1 x 1011^{11} m. Calculate the centripetal force acting on the electron.

  1. A.7.7 x 1047^{47} N
  2. B.6.0 x 10−8^{-8}N
  3. C.3.0 x 10−14^{-14}N
  4. D.1.3 x 10−26^{-26}N

Answer: B. 6.0 x 10−8^{-8}N

Explanation written with AI and checked against the answer key

Analyze the question: We need the centripetal force on an electron moving in a circle. The formula is F = mv²/r.

Given:

  • m = 9.1 × 10⁻³¹ kg
  • v = 2.0 × 10⁶ m/s
  • r = 6.1 × 10¹¹ m (as printed)

Calculation with the radius as printed:

v² = 4.0 × 10¹² m²/s²

mv² = 9.1 × 10⁻³¹ × 4.0 × 10¹² = 3.64 × 10⁻¹⁸

F = 3.64 × 10⁻¹⁸ / 6.1 × 10¹¹ ≈ 6.0 × 10⁻³⁰ N

This matches none of the options. The radius of an atom's orbit cannot be 10¹¹ m, since that is larger than the Earth. The original question almost certainly has r = 6.1 × 10⁻¹¹ m, and the minus sign was lost in the formatting.

Calculation with r = 6.1 × 10⁻¹¹ m:

F = 3.64 × 10⁻¹⁸ / 6.1 × 10⁻¹¹

F ≈ 0.597 × 10⁻⁷ ≈ 6.0 × 10⁻⁸ N

Note: With the radius exactly as typed (10¹¹), the answer would be about 6.0 × 10⁻³⁰ N, which is not listed. So the question as pasted has a typo, and the intended radius is 6.1 × 10⁻¹¹ m. Check your question paper to confirm.

Tip: Always check that the powers of ten make physical sense. Atomic radii are around 10⁻¹⁰ m, so a positive exponent signals a typo. Also, write F = mv²/r and combine the powers of ten separately from the numbers to avoid slips.

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