WAEC 2019 Physics · Question 22
An electron of mass 9.1 x 10 ^ -31 kg moves with a speed of 2.0 x 10 ^6 ms ^ -1 round the nucleus of an atom…
Question
An electron of mass 9.1 x 10 kg moves with a speed of 2.0 x 10 ms round the nucleus of an atom in a Circular path of radius 6.1 x 10 m. Calculate the centripetal force acting on the electron.
- A.7.7 x 10 N
- B.6.0 x 10N
- C.3.0 x 10N
- D.1.3 x 10N
Answer: B. 6.0 x 10N
Explanation written with AI and checked against the answer key
Analyze the question: We need the centripetal force on an electron moving in a circle. The formula is F = mv²/r.
Given:
- m = 9.1 × 10⁻³¹ kg
- v = 2.0 × 10⁶ m/s
- r = 6.1 × 10¹¹ m (as printed)
Calculation with the radius as printed:
v² = 4.0 × 10¹² m²/s²
mv² = 9.1 × 10⁻³¹ × 4.0 × 10¹² = 3.64 × 10⁻¹⁸
F = 3.64 × 10⁻¹⁸ / 6.1 × 10¹¹ ≈ 6.0 × 10⁻³⁰ N
This matches none of the options. The radius of an atom's orbit cannot be 10¹¹ m, since that is larger than the Earth. The original question almost certainly has r = 6.1 × 10⁻¹¹ m, and the minus sign was lost in the formatting.
Calculation with r = 6.1 × 10⁻¹¹ m:
F = 3.64 × 10⁻¹⁸ / 6.1 × 10⁻¹¹
F ≈ 0.597 × 10⁻⁷ ≈ 6.0 × 10⁻⁸ N
Note: With the radius exactly as typed (10¹¹), the answer would be about 6.0 × 10⁻³⁰ N, which is not listed. So the question as pasted has a typo, and the intended radius is 6.1 × 10⁻¹¹ m. Check your question paper to confirm.
Tip: Always check that the powers of ten make physical sense. Atomic radii are around 10⁻¹⁰ m, so a positive exponent signals a typo. Also, write F = mv²/r and combine the powers of ten separately from the numbers to avoid slips.
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