WAEC 2017 Physics · Question 10

A transformer connected to a 240Vr.m.sV_{r.m.s} has 3000 turns in its primary coil and 500 turns in its secondary coil. Calculate the output voltage.

Options

  1. A.4000V
  2. B.400V
  3. C.40V
  4. D.4V

Answer: C. 40V

Explanation written with AI and checked against the answer key

Analyze the question: This is an ideal transformer problem. We're given the input (primary) voltage and the number of turns in each coil, and we need the output (secondary) voltage.

Concept: For a transformer, the voltage ratio equals the turns ratio:

VsVp=NsNp\frac{V_s}{V_p} = \frac{N_s}{N_p}

where

  • V_p = primary voltage = 240 V
  • V_s = secondary voltage (what we want)
  • N_p = primary turns = 3000
  • N_s = secondary turns = 500

Solution:

Vs=Vp×NsNpV_s = V_p \times \frac{N_s}{N_p}
Vs=240×5003000V_s = 240 \times \frac{500}{3000}
Vs=240×16V_s = 240 \times \frac{1}{6}
Vs=40 VV_s = 40 \text{ V}

Since the secondary has fewer turns than the primary, this is a step-down transformer, so the output voltage is smaller than 240 V. That agrees with our answer of 40 V.

Answer: The output voltage is 40 V (r.m.s.), which is option C.

Tip: Always check the direction. If N_s < N_p, the voltage steps down. If N_s > N_p, it steps up. This lets you quickly eliminate options like A (4000 V) and B (400 V), which are larger than the input. Also, simplify the turns ratio first (500/3000 = 1/6) to make the arithmetic easy without a calculator.

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