WAEC 2016 Physics · Question 34

In a p-type semiconductor, the?

Options

  1. A.number of holes are equal to the number of electrons
  2. B.electrical resistivity increases
  3. C.electrons are the majority charge carriers
  4. D.holes are the majority charge carriers

Answer: D. holes are the majority charge carriers

Explanation written with AI and checked against the answer key

Analyze the question: It asks what is true of a p-type semiconductor, which is a basic fact about doping.

Concept:

  • A pure (intrinsic) semiconductor such as silicon or germanium has equal numbers of electrons and holes.
  • Doping with a trivalent impurity (e.g., boron, aluminium, gallium, indium) gives a p-type semiconductor. Each trivalent atom has only 3 valence electrons, so it leaves a vacancy in a covalent bond. This vacancy is called a hole.
  • Doping with a pentavalent impurity (e.g., phosphorus, arsenic, antimony) gives an n-type semiconductor, where electrons are the majority carriers.

Step by step:

  1. A trivalent atom replaces a silicon atom in the crystal lattice.
  2. It forms only 3 complete covalent bonds, so one bond is missing an electron, which creates a hole.
  3. Many holes are therefore available to carry current (they are "positive" charge carriers).
  4. So in p-type material, holes are the majority carriers and electrons are the minority carriers.

Checking the options:

  • A. Holes equal to electrons: this is true of intrinsic semiconductors, not p-type. ✗
  • B. Resistivity increases: doping adds charge carriers, so resistivity decreases. ✗
  • C. Electrons are the majority carriers: this describes n-type. ✗
  • D. Holes are the majority carriers: ✓

Tip: Think "P = Positive holes" and "N = Negative electrons". Also remember that trivalent impurities give p-type (3 → p) and pentavalent impurities give n-type.

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