WAEC 2016 Physics · Question 34
In a p-type semiconductor, the?
Options
- A.number of holes are equal to the number of electrons
- B.electrical resistivity increases
- C.electrons are the majority charge carriers
- D.holes are the majority charge carriers
Answer: D. holes are the majority charge carriers
Explanation written with AI and checked against the answer key
Analyze the question: It asks what is true of a p-type semiconductor, which is a basic fact about doping.
Concept:
- A pure (intrinsic) semiconductor such as silicon or germanium has equal numbers of electrons and holes.
- Doping with a trivalent impurity (e.g., boron, aluminium, gallium, indium) gives a p-type semiconductor. Each trivalent atom has only 3 valence electrons, so it leaves a vacancy in a covalent bond. This vacancy is called a hole.
- Doping with a pentavalent impurity (e.g., phosphorus, arsenic, antimony) gives an n-type semiconductor, where electrons are the majority carriers.
Step by step:
- A trivalent atom replaces a silicon atom in the crystal lattice.
- It forms only 3 complete covalent bonds, so one bond is missing an electron, which creates a hole.
- Many holes are therefore available to carry current (they are "positive" charge carriers).
- So in p-type material, holes are the majority carriers and electrons are the minority carriers.
Checking the options:
- A. Holes equal to electrons: this is true of intrinsic semiconductors, not p-type. ✗
- B. Resistivity increases: doping adds charge carriers, so resistivity decreases. ✗
- C. Electrons are the majority carriers: this describes n-type. ✗
- D. Holes are the majority carriers: ✓
Tip: Think "P = Positive holes" and "N = Negative electrons". Also remember that trivalent impurities give p-type (3 → p) and pentavalent impurities give n-type.
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