WAEC 2015 Physics · Question 22
A girl standing some distance from the cliff claps her hands and hears the echo 0.8s later. calculate her…
Question
A girl standing some distance from the cliff claps her hands and hears the echo 0.8s later. calculate her distance from the cliff. [speed of sound in air = 320 ]
- A.23m
- B.128m
- C.288m
- D.298m
Answer: B. 128m
Explanation written with AI and checked against the answer key
Analyze the question: An echo is sound that travels from the girl to the cliff and then back to her. The 0.8 s is the time for the round trip, so the sound covers twice her distance from the cliff.
Concept: Speed = distance ÷ time, so the total distance travelled = speed × time. For an echo: 2d = v × t, so d = vt / 2
Solution:
- v = 320 m/s
- t = 0.8 s
Total distance travelled by the sound: 2d = 320 × 0.8 = 256 m
Distance from the cliff: d = 256 ÷ 2 = 128 m
Answer: B (128 m)
Common mistakes:
- Using d = 320 × 0.8 = 256 m, forgetting to halve it. That value isn't in the options, which hints you missed a step.
- Always check whether the time given is for a one-way or round trip.
Tip: For any echo question, remember "echo = there and back", so use d = vt/2. If the time is given as the time to hear the echo, always divide by 2.
AI can make mistakes. Report anything that looks wrong.
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