WAEC 2015 Physics · Question 22

A girl standing some distance from the cliff claps her hands and hears the echo 0.8s later. calculate her…

Question

A girl standing some distance from the cliff claps her hands and hears the echo 0.8s later. calculate her distance from the cliff. [speed of sound in air = 320 ms−1ms^{-1}]

  1. A.23m
  2. B.128m
  3. C.288m
  4. D.298m

Answer: B. 128m

Explanation written with AI and checked against the answer key

Analyze the question: An echo is sound that travels from the girl to the cliff and then back to her. The 0.8 s is the time for the round trip, so the sound covers twice her distance from the cliff.

Concept: Speed = distance ÷ time, so the total distance travelled = speed × time. For an echo: 2d = v × t, so d = vt / 2

Solution:

  • v = 320 m/s
  • t = 0.8 s

Total distance travelled by the sound: 2d = 320 × 0.8 = 256 m

Distance from the cliff: d = 256 ÷ 2 = 128 m

Answer: B (128 m)

Common mistakes:

  • Using d = 320 × 0.8 = 256 m, forgetting to halve it. That value isn't in the options, which hints you missed a step.
  • Always check whether the time given is for a one-way or round trip.

Tip: For any echo question, remember "echo = there and back", so use d = vt/2. If the time is given as the time to hear the echo, always divide by 2.

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