WAEC 2014 Physics · Question 8

an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the…

Question

an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the observer from the cliff. [speed of sound in air = 330ms−1ms^{-1}]

  1. A.104.4m
  2. B.207.9m
  3. C.415.8m
  4. D.523.8m

Answer: B. 207.9m

Explanation written with AI and checked against the answer key

Analyze the question

The sound travels from the observer to the cliff and back again. The echo time of 1.26 s therefore covers twice the distance between the observer and the cliff.

Concept

Speed = distance ÷ time, so total distance = speed × time.

For an echo: 2d = v × t d = (v × t) / 2

Solution

  • v = 330 m/s
  • t = 1.26 s

2d = 330 × 1.26 = 415.8 m

d = 415.8 / 2 = 207.9 m

Answer

The observer is 207.9 m from the cliff.

Tip

Whenever you see "echo", divide by 2. Option C (415.8 m) is the trap answer: it is the total distance travelled by the sound, not the distance to the cliff. Always ask yourself, "Is this the one-way distance or the round trip?"

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