WAEC 2014 Physics · Question 8
an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the…
Question
an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the observer from the cliff. [speed of sound in air = 330]
- A.104.4m
- B.207.9m
- C.415.8m
- D.523.8m
Answer: B. 207.9m
Explanation written with AI and checked against the answer key
Analyze the question
The sound travels from the observer to the cliff and back again. The echo time of 1.26 s therefore covers twice the distance between the observer and the cliff.
Concept
Speed = distance ÷ time, so total distance = speed × time.
For an echo: 2d = v × t d = (v × t) / 2
Solution
- v = 330 m/s
- t = 1.26 s
2d = 330 × 1.26 = 415.8 m
d = 415.8 / 2 = 207.9 m
Answer
The observer is 207.9 m from the cliff.
Tip
Whenever you see "echo", divide by 2. Option C (415.8 m) is the trap answer: it is the total distance travelled by the sound, not the distance to the cliff. Always ask yourself, "Is this the one-way distance or the round trip?"
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