WAEC 2014 Physics · Question 32

An ammeter can be adapted to measure potential difference by using a

Options

  1. A.shunt
  2. B.multiplier
  3. C.rheostat
  4. D.resistance box

Answer: B. multiplier

Explanation written with AI and checked against the answer key

Analyze the question: An ammeter is built from a sensitive galvanometer. We want to make it read potential difference (voltage), so it must work like a voltmeter.

Explain the concept:

  • A shunt is a low resistance connected in parallel with a galvanometer. It lets most of the current bypass the coil, which extends the current range. This makes an ammeter.
  • A multiplier is a high resistance connected in series with a galvanometer. It limits the current through the coil and makes the instrument read voltage, which makes a voltmeter.
  • A rheostat is a variable resistor used to control current in a circuit.
  • A resistance box is a set of known resistors used for experiments. It is not a standard way to convert a meter.

Step-by-step solution:

  1. Voltage is measured by a voltmeter, which has a high resistance.
  2. To get a high total resistance from a galvanometer or ammeter, add a large resistance in series.
  3. The voltage across the meter is V = I(R_g + R_m). So the scale can be calibrated in volts, with R_m = V/I_g − R_g.
  4. The series resistor that does this is called a multiplier.

Answer: The correct option is B. multiplier.

Exam tip: Remember "Shunt = Parallel = Ammeter" and "Multiplier = Series = Voltmeter". The letters S-P-A and M-S-V can help you recall them.

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