WAEC 2014 Physics · Question 32
An ammeter can be adapted to measure potential difference by using a
Options
- A.shunt
- B.multiplier
- C.rheostat
- D.resistance box
Answer: B. multiplier
Explanation written with AI and checked against the answer key
Analyze the question: An ammeter is built from a sensitive galvanometer. We want to make it read potential difference (voltage), so it must work like a voltmeter.
Explain the concept:
- A shunt is a low resistance connected in parallel with a galvanometer. It lets most of the current bypass the coil, which extends the current range. This makes an ammeter.
- A multiplier is a high resistance connected in series with a galvanometer. It limits the current through the coil and makes the instrument read voltage, which makes a voltmeter.
- A rheostat is a variable resistor used to control current in a circuit.
- A resistance box is a set of known resistors used for experiments. It is not a standard way to convert a meter.
Step-by-step solution:
- Voltage is measured by a voltmeter, which has a high resistance.
- To get a high total resistance from a galvanometer or ammeter, add a large resistance in series.
- The voltage across the meter is V = I(R_g + R_m). So the scale can be calibrated in volts, with R_m = V/I_g − R_g.
- The series resistor that does this is called a multiplier.
Answer: The correct option is B. multiplier.
Exam tip: Remember "Shunt = Parallel = Ammeter" and "Multiplier = Series = Voltmeter". The letters S-P-A and M-S-V can help you recall them.
AI can make mistakes. Report anything that looks wrong.
Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.
