WAEC 2014 Physics · Question 24

A wire of length 100 cm has a resistance of 10Ω\Omega. If its cross-sectional area is 0.005cm2, determine its resistivity

Options

  1. A.0.0005Ω\Omegacm
  2. B.0.0015Ω\Omegacm
  3. C.0.0016Ω\Omegacm
  4. D.0.0700Ω\Omegacm

Answer: A. 0.0005Ω\Omegacm

Explanation written with AI and checked against the answer key

Analyze the question: We are given a wire's length, resistance and cross-sectional area, and we must find its resistivity.

Concept: Resistance depends on the material and the wire's dimensions:

R = ρL / A, so ρ = RA / L

Solution:

  • R = 10 Ω
  • A = 0.005 cm²
  • L = 100 cm

ρ = (10 × 0.005) / 100 ρ = 0.05 / 100 ρ = 0.0005 Ω cm

Check on units: Ω × cm² ÷ cm = Ω cm, which matches the options, so there is no need to convert to metres.

Answer: The resistivity is 0.0005 Ω cm.

Tip: Keep length and area in the same unit system (all cm, or all m). Then the unit of resistivity follows directly (Ω cm or Ω m). Also remember ρ = RA/L by thinking "Resistance Area over Length".

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.