WAEC 2011 Physics · Question 29
The radius of a wheel is 30.0 cm and that of its axle is 6.0cm. Calculate the effort required to lift a load…
Question
The radius of a wheel is 30.0 cm and that of its axle is 6.0cm. Calculate the effort required to lift a load of 120.0N using this machine. Assuming 100% efficiency
- A.600.0N
- B.40.0N
- C.24.0N
- D.20.0N
Answer: C. 24.0N
Explanation written with AI and checked against the answer key
Analyze the question: This is a wheel and axle machine. We need the effort that lifts a 120.0 N load, assuming 100% efficiency.
Concept:
- Velocity ratio (VR) = radius of wheel / radius of axle
- Mechanical advantage (MA) = Load / Effort
- Efficiency = MA / VR × 100%
At 100% efficiency, MA = VR.
Solution:
- VR = R / r = 30.0 / 6.0 = 5
- Efficiency = 100%, so MA = VR = 5
- MA = Load / Effort, so
Effort = Load / MA = 120.0 / 5 = 24.0 N
Check: Effort × wheel radius = Load × axle radius, so 24 × 30 = 720 and 120 × 6 = 720. ✔
Answer: The effort required is 24.0 N, which is option C.
Tip: For a wheel and axle, the effort acts on the larger radius and the load on the smaller one, so the effort is always smaller than the load when efficiency is 100%. If you get an effort bigger than the load, you have flipped the ratio. Also remember that "100% efficiency" means MA = VR.
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