The image formed by a convex mirror is always

Analyze the question: The question asks about the nature of the image a convex (diverging) mirror always forms, regardless of where the object is placed.

Concept: A convex mirror curves outward. Parallel rays hitting it diverge after reflection, so they never actually meet in front of the mirror. They only appear to come from a point behind the mirror, which is the virtual focus.

Step by step:

1. Real or virtual? Reflected rays diverge and only appear to meet behind the mirror. The image is therefore virtual. Real images need rays that actually converge, and a convex mirror cannot do that for a real object.

2. Erect or inverted? A virtual image formed by a single mirror like this is on the same side up as the object, so it is erect.

3. Size? Using the mirror formula 1/f = 1/u + 1/v, with f taken as negative for a convex mirror (real-is-positive convention), the image distance |v| is always less than the object distance |u|. Magnification m = -v/u has a magnitude less than 1, so the image is diminished.

4. Position: The image always lies between the pole and the principal focus, behind the mirror.

Checking the options:

• A. Real, erect, diminished: wrong, because the image is never real.
• B. Real, inverted, diminished: wrong, because the image is never real or inverted.
• C. Virtual, inverted, diminished: wrong, because the image is not inverted.
• D. Virtual, erect, diminished: correct.

Exam tip: Remember "convex = always the same story": virtual, erect, diminished, and located behind the mirror. This is why convex mirrors are used as vehicle rear-view mirrors and for security mirrors in shops. They give a wide field of view with a smaller, upright image. Only a concave mirror changes its image type depending on the object's position.