WAEC 2011 Physics · Question 8
A stone of mass 300g is released from rest from the top of a bulding of height 100m. Determine the kinetic…
Question
A stone of mass 300g is released from rest from the top of a bulding of height 100m. Determine the kinetic energy gained by the stone when it is a quarter way down from the point of release.[g = 10 ]
- A.750.0J
- B.225.0J
- C.75.0J
- D.22.5J
Answer: C. 75.0J
Explanation written with AI and checked against the answer key
Analyze the question: A stone falls from rest. We need the kinetic energy gained after it has fallen a quarter of the building's height.
Concept: By conservation of energy (ignoring air resistance), the kinetic energy gained equals the potential energy lost:
KE gained = mgh, where h is the distance fallen.
Solution:
- Mass: m = 300 g = 0.3 kg
- Distance fallen: h = ¼ × 100 m = 25 m
- g = 10 m/s²
KE = mgh = 0.3 × 10 × 25 = 75 J
Check using kinematics: v² = u² + 2gh = 0 + 2(10)(25) = 500 KE = ½mv² = ½ × 0.3 × 500 = 75 J ✓
Answer: C. 75.0J
Tip: Watch the units. Always convert grams to kilograms before calculating (300 g = 0.3 kg). Using 300 directly would give 75,000 J, which isn't an option. Also note that "a quarter way down" means the distance fallen is 25 m, not the height remaining (75 m). If you used 75 m, you'd get 225 J (option B), which is a common trap.
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