WAEC 2011 Physics · Question 44
A ray undergoes a minimum deviation at 40o when it is incident on equilateral triangular glass prism. Calculate the refractive index of the prism
Options
- A.1.48
- B.1.50
- C.1.53
- D.1.67
Answer: C. 1.53
Explanation written with AI and checked against the answer key
Analyze the question
A ray passes through an equilateral prism, so the prism angle is A = 60°. The minimum deviation is D = 40°. We need the refractive index n.
Concept
At minimum deviation, the prism formula is:
n = sin[(A + D)/2] / sin(A/2)
Solution
- (A + D)/2 = (60° + 40°)/2 = 50°
- A/2 = 30°
- n = sin 50° / sin 30°
- sin 50° = 0.7660 and sin 30° = 0.5
- n = 0.7660 / 0.5 = 1.532
So n ≈ 1.53.
Answer
Tip
For minimum deviation questions, remember that sin 30° = 0.5, so the answer is simply 2 × sin[(A + D)/2]. Learn sin 50° ≈ 0.766, sin 45° ≈ 0.707 and sin 60° ≈ 0.866 so you can work quickly without tables. Also, "equilateral prism" always means A = 60°.
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