WAEC 2011 Physics · Question 44

A ray undergoes a minimum deviation at 40o when it is incident on equilateral triangular glass prism. Calculate the refractive index of the prism

Options

  1. A.1.48
  2. B.1.50
  3. C.1.53
  4. D.1.67

Answer: C. 1.53

Explanation written with AI and checked against the answer key

Analyze the question

A ray passes through an equilateral prism, so the prism angle is A = 60°. The minimum deviation is D = 40°. We need the refractive index n.

Concept

At minimum deviation, the prism formula is:

n = sin[(A + D)/2] / sin(A/2)

Solution

  1. (A + D)/2 = (60° + 40°)/2 = 50°
  2. A/2 = 30°
  3. n = sin 50° / sin 30°
  4. sin 50° = 0.7660 and sin 30° = 0.5
  5. n = 0.7660 / 0.5 = 1.532

So n ≈ 1.53.

Answer

Tip

For minimum deviation questions, remember that sin 30° = 0.5, so the answer is simply 2 × sin[(A + D)/2]. Learn sin 50° ≈ 0.766, sin 45° ≈ 0.707 and sin 60° ≈ 0.866 so you can work quickly without tables. Also, "equilateral prism" always means A = 60°.

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