WAEC 2010 Physics · Question 3
An electric drill rated 400W is used to drill a hole in copper of mass 400g in 20s. Calculate the rise in…
Question
An electric drill rated 400W is used to drill a hole in copper of mass 400g in 20s. Calculate the rise in temperature if all the heat produced is absorbed by the copper. [specific heat capacity of copper = 400Jkg-1K-1]
- A.100oC
- B.75oC
- C.50oC
- D.45oC
Answer: C. 50oC
Explanation written with AI and checked against the answer key
Analyze the question: A drill of known power runs for a known time, and all its energy becomes heat in the copper. We need the temperature rise.
Concept:
- Energy supplied: E = P × t
- Heat absorbed: Q = mcΔθ
- Since all the energy is absorbed, P × t = mcΔθ
Solution:
- Energy produced: E = P × t = 400 W × 20 s = 8000 J
- Convert the mass to kg: m = 400 g = 0.4 kg
- Equate energy to heat absorbed: 8000 = 0.4 × 400 × Δθ 8000 = 160 × Δθ
- Solve for Δθ: Δθ = 8000 ÷ 160 = 50 K (50 °C)
A temperature rise in kelvin equals the rise in °C, so the answer is 50 °C.
Tip: Always convert grams to kilograms before using Q = mcΔθ. Forgetting this is the most common mistake. If you had used 400 g directly, you would have gotten 0.05, which is not among the options. Also remember that Power × Time gives Energy (W × s = J).
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