WAEC 2010 Physics · Question 38
a thermometer records 680 mmHg at steam point and 440 mmHg at ice point. The temperature it records at 380 mmHg is
Options
- A.-25oC
- B.-20oC
- C.20oC
- D.25oC
Answer: A. -25oC
Explanation written with AI and checked against the answer key
Analyze the question
This is a thermometer that uses a physical property (here, pressure in mmHg) to measure temperature. The fixed points are:
- Steam point (100°C): 680 mmHg
- Ice point (0°C): 440 mmHg
We need the temperature when the reading is 380 mmHg.
Concept
For a linear thermometric property, the temperature is:
θ = [(X_θ − X_ice) / (X_steam − X_ice)] × 100°C
Solution
- X_θ − X_ice = 380 − 440 = −60
- X_steam − X_ice = 680 − 440 = 240
θ = (−60 / 240) × 100 θ = −0.25 × 100 θ = −25°C
The reading of 380 mmHg is below the ice-point reading of 440 mmHg, so the temperature must be below 0°C. That means the answer has to be negative, which rules out C and D straight away.
Tip
Always use the formula (reading − lower fixed point) ÷ (upper fixed point − lower fixed point) × 100. Then check the sign: if the reading is below the ice-point value, the temperature is negative.
AI can make mistakes. Report anything that looks wrong.
Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.
