WAEC 2010 Physics · Question 8
A ray of light travels from air to water. The refeactive index of water is given by the expression
Options
- A.
- B.
- C.
- D.
Answer: D.
Explanation written with AI and checked against the answer key
Analyze the question: A ray goes from air into water. We need the correct expression for the refractive index of water (relative to air).
Concept: Refractive index n for light going from medium 1 (air) to medium 2 (water) can be written in several equivalent ways:
- n = sin i / sin r (angle of incidence over angle of refraction)
- n = velocity in air / velocity in water
- n = wavelength in air / wavelength in water (frequency stays constant, so v = fλ gives the same ratio as the velocities)
- n = real depth / apparent depth
Check each option:
- A. velocity in water / velocity in air. This is inverted. It would be less than 1, but n for water is about 1.33. Wrong.
- B. sin r / sin i. This is also inverted. The correct form is sin i / sin r. Wrong.
- C. apparent depth / real depth. Also inverted. The correct form is real depth / apparent depth. Wrong.
- D. wavelength in air / wavelength in water. Since v = fλ and f does not change when light enters a new medium, n = v_air / v_water = λ_air / λ_water. Correct.
Tip: Remember that refractive index is always bigger than 1 for water. So the "faster" or "larger" quantity (air's speed, air's wavelength, real depth, sin i) goes on top. Options A, B and C each flip one of these, and that is the usual trap in this question.
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