WAEC 2010 Physics · Question 10
A certain wave has a speed of 20. If the frequency of the wave is 0.25Hz, calculate the distance between successive crests of the wave
Options
- A.5.0m
- B.40.0m
- C.50.0m
- D.80.0m
Answer: D. 80.0m
Explanation written with AI and checked against the answer key
Analyze the question: The distance between successive crests is the wavelength (λ). We are given the wave speed and the frequency.
Concept: The wave equation is
v = fλ, so λ = v / f
Solution:
- v = 20 m/s
- f = 0.25 Hz
λ = 20 / 0.25 = 80 m
Answer: The wavelength is 80 m, which is option D.
Check: A frequency of 0.25 Hz means the period is T = 1/0.25 = 4 s. In 4 seconds the wave travels 20 × 4 = 80 m, which is exactly one wavelength. ✔
Tip: Dividing by 0.25 is the same as multiplying by 4, so 20 ÷ 0.25 = 20 × 4 = 80. Also remember that "distance between successive crests" always means wavelength. The same applies to "distance between successive troughs".
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