WAEC 2024 Mathematics · Question 49

Make R the subject of the relation V = πl(R2^2 - r2^2)

Options

  1. A.R = Vπl+ r2\sqrt{\frac{V}{πl} + r^2}
  2. B.R = Vπl− r2\sqrt{\frac{V}{πl} - r^2}
  3. C.R = V− πlr2\sqrt{V - πlr^2}
  4. D.R = V+ πlr2\sqrt{V + πlr^2}

Answer: A. R = Vπl+ r2\sqrt{\frac{V}{πl} + r^2}

Explanation written with AI and checked against the answer key

Analyze the question: We need to rearrange V = πl(R² − r²) so that R stands alone on one side.

Concept: Use inverse operations to undo what has been done to R, working from the outside in: undo the multiplication, then the subtraction, then the square.

Solution:

  1. Start with the formula: V = πl(R² − r²)
  1. Divide both sides by πl: V/(πl) = R² − r²
  1. Add r² to both sides: R² = V/(πl) + r²
  1. Take the square root of both sides (R is a positive length): R = √(V/(πl) + r²)

Checking the options:

  • A: √(V/(πl) + r²) matches our result.
  • B has a minus sign, which is wrong because r² is added, not subtracted.
  • C and D fail to divide V by πl properly. They multiply πlr² instead.

Answer: A

Tip: When making a variable the subject, "undo" operations in reverse order of BODMAS. Here the bracket was multiplied by πl, so divide first. Then move −r² across, which becomes +r². Finally, take the square root. Always remember that moving a term across the equals sign changes its sign.

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