WAEC 2023 Mathematics · Question 23

Mrs Kebeh stands at a distance of 110 m away from a building of vertical height 58 m. If Kebeh is 2 m tall…

Question

Mrs Kebeh stands at a distance of 110 m away from a building of vertical height 58 m. If Kebeh is 2 m tall, find the angle of elevation of the top of the building from her eye.

  1. A.27027^0
  2. B.28028^0
  3. C.20020^0
  4. D.26026^0

Answer: A. 27027^0

Explanation written with AI and checked against the answer key

Analyze the question: Mrs Kebeh's eye is at a height of about 2 m (we treat her height as the eye level). The building is 58 m tall, so the part of the building above her eye level is 58 − 2 = 56 m. She stands 110 m from the building.

Concept: The angle of elevation θ is found from a right-angled triangle using

tan θ = opposite / adjacent

Solution:

  • Opposite side = 58 − 2 = 56 m
  • Adjacent side = 110 m

tan θ = 56/110 = 0.5091

θ = tan⁻¹(0.5091)

Checking known values: tan 27° ≈ 0.5095, so θ ≈ 27°.

(If you had wrongly used 58 m, tan θ = 58/110 = 0.527, giving about 28°. That is the trap in option B, because the 2 m height must be subtracted.)

Answer: The angle of elevation is about 27°, which is option A.

Tip: Always subtract the observer's height from the object's height when the angle is measured from the eye. Also remember tan 27° ≈ 0.51, which is handy for questions like this.

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.