WAEC 2022 Mathematics · Question 46

Make t the subject of k = mt−prm \sqrt \frac{t-p}{r}

Options

  1. A.k2r+pm2\frac{k^2r + p}{m^2}
  2. B.k2r+pm2m2\frac{k^2r + pm^2}{m^2}
  3. C.k2r−pm2\frac{k^2r - p}{m^2}
  4. D.k2r+p2m2\frac{k^2r + p^2}{m^2}

Answer: B. k2r+pm2m2\frac{k^2r + pm^2}{m^2}

Explanation written with AI and checked against the answer key

Analyze the question: We need to rearrange k = m√((t − p)/r) so that t stands alone on one side.

Concept: To remove a square root, square both sides. Then use inverse operations to isolate t.

Solution:

  1. Start with: k = m√((t − p)/r)
  1. Divide both sides by m: k/m = √((t − p)/r)
  1. Square both sides: k²/m² = (t − p)/r
  1. Multiply both sides by r: k²r/m² = t − p
  1. Add p to both sides: t = k²r/m² + p
  1. Combine over a common denominator: t = (k²r + pm²)/m²

Matching to the options: This is exactly option B, (k²r + pm²)/m².

Check the others:

  • A, (k²r + p)/m², would be wrong because p was not multiplied by m² when combining the fractions.
  • C has the wrong sign and the same missing m².
  • D uses p² instead of pm², which has no basis in the working.

Tip: When you have a "subject of the formula" question with a square root, always follow this order: isolate the root, square both sides, then clear the fractions. When you add a plain term like p to a fraction with denominator m², remember to multiply it by m² to get a common denominator. That is where many students lose marks.

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