WAEC 2021 Mathematics · Question 46

A solid brass cube is melted and recast as a solid cone of height h and base radius r. If the height of the cube is h, find r in terms of h.

Options

  1. A.r = h
  2. B.r = √3h2π\frac{3h^2}{π}
  3. C.r = πh
  4. D.r = h √3h\frac{3}{h}

Answer: B. r = √3h2π\frac{3h^2}{π}

Explanation written with AI and checked against the answer key

Analyze the question: A cube of side h is melted and recast as a cone of height h and base radius r. Melting and recasting does not change the volume, so the two volumes are equal.

Concept:

  • Volume of a cube = h³ (the side of the cube is h)
  • Volume of a cone = (1/3)πr²h

Solution:

Set the volumes equal:

h³ = (1/3)πr²h

Divide both sides by h:

h² = (1/3)πr²

Multiply both sides by 3:

3h² = πr²

Divide by π:

r² = 3h²/π

Take the square root:

r = √(3h²/π) (equivalently, r = h√(3/π))

Checking the options:

  • A. r = h is wrong, because it would need π/3 = 1.
  • B. r = √(3h²/π) matches our result exactly.
  • C. r = πh is wrong.
  • D. r = h√(3/h) is wrong, because the factor under the root should be 3/π, not 3/h. It looks similar, so be careful.

Tip: In "melted and recast" questions, always equate the volumes. Cancel any common factor (here h) early to keep the algebra short. Also check that the π appears in the right place when comparing options.

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