WAEC 2017 Mathematics · Question 16

Three exterior angles of a polygon are 30o^o, 40o^o and 60o^o. If the remaining exterior angles are 46o^o each, name the polygon.

Options

  1. A.decagon
  2. B.nonagon
  3. C.octagon
  4. D.hexagon

Answer: C. octagon

Explanation written with AI and checked against the answer key

Concept: The sum of the exterior angles of any polygon is 360°. A polygon with n sides has n exterior angles. Step 1: Add the known exterior angles 30° + 40° + 60° = 130° Step 2: Find what is left for the remaining angles 360° − 130° = 230° Step 3: Divide by 46° to find how many remaining angles there are 230° ÷ 46° = 5 Step 4: Count all the sides n = 3 + 5 = 8 sides A polygon with 8 sides is an octagon. Check: 130° + 5(46°) = 130° + 230° = 360° ✓ Tip: For questions like this, always start with "exterior angles add up to 360°". Subtract the known angles, divide by the repeated angle, then add back the number of known angles. Also remember the names: 5 pentagon, 6 hexagon, 7 heptagon, 8 octagon, 9 nonagon, 10 decagon.

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