WAEC 2016 Mathematics · Question 38

Simplify; 21−x−1x\frac{2}{1 - x} - \frac{1}{x}

Options

  1. A.x+1x(1−x)\frac{x + 1}{x(1 - x)}
  2. B.3x−1x(1−x)\frac{3x - 1}{ x(1 - x)}
  3. C.3x+1x(1−x)\frac{3x + 1}{ x(1 - x)}
  4. D.x−1x(1−x)\frac{x - 1}{ x(1 - x)}

Answer: B. 3x−1x(1−x)\frac{3x - 1}{ x(1 - x)}

Explanation written with AI and checked against the answer key

Analyze the question: We need to combine two fractions with different denominators, (1 − x) and x, into a single fraction.

Concept: To subtract fractions, find a common denominator. Here it is x(1 − x). Multiply each fraction's numerator by whatever is missing from its denominator.

Solution:

21−x−1x=2⋅x−1⋅(1−x)x(1−x)\frac{2}{1-x} - \frac{1}{x} = \frac{2\cdot x - 1\cdot(1-x)}{x(1-x)}

Expand the numerator:

2x−(1−x)=2x−1+x=3x−12x - (1 - x) = 2x - 1 + x = 3x - 1

So:

21−x−1x=3x−1x(1−x)\frac{2}{1-x} - \frac{1}{x} = \frac{3x-1}{x(1-x)}

Check with a value: Let x = 2.

  • Original: 2/(1−2) − 1/2 = −2 − 0.5 = −2.5
  • Option B: (3(2) − 1)/(2(1−2)) = 5/(−2) = −2.5 ✓

Answer: Option B.

Tip: The most common mistake is forgetting that the minus sign applies to the whole of (1 − x), which gives −1 + x, not −1 − x. Always put brackets around the numerator being subtracted. A quick check by substituting a number such as x = 2 can confirm your answer in seconds.

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