WAEC 2015 Mathematics · Question 10
Simplify:
Options
- A.
- B.
- C.
- D.
Answer: D.
Explanation written with AI and checked against the answer key
Step 1: Analyze the question We need to combine three fractions into one. The first step is to find a common denominator.
Step 2: Concept The denominators are xy, 2xy and 2. The LCM is 2xy, so we rewrite every fraction with denominator 2xy.
Step 3: Solution
- First fraction: (3x − y)/(xy) = 2(3x − y)/(2xy) = (6x − 2y)/(2xy)
- Second fraction: (2x + 3y)/(2xy), already over 2xy
- Third fraction: 1/2 = xy/(2xy)
Now combine them:
[(6x − 2y) − (2x + 3y) + xy] / (2xy)
Be careful with the minus sign in front of the second bracket:
= (6x − 2y − 2x − 3y + xy) / (2xy)
= (4x − 5y + xy) / (2xy)
Step 4: Answer
Step 5: Tip When subtracting a fraction whose numerator has more than one term, put that numerator in brackets first. Sign errors, such as forgetting to change +3y to −3y, are the most common way to lose marks on this type of question. Options A, B and C come from exactly those kinds of slips.
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