WAEC 2014 Mathematics · Question 21
The coordinates of points P and Q are (4, 3) and (2, -1) respectively. Find the shortest distance between P and Q.
Options
- A.10
- B.4
- C.5
- D.2
Answer: D. 2
Explanation written with AI and checked against the answer key
Analyze the question: The shortest distance between two points is the straight-line distance, so we use the distance formula.
Concept: For points (x₁, y₁) and (x₂, y₂):
d = √[(x₂ − x₁)² + (y₂ − y₁)²]
Solution:
P(4, 3) and Q(2, −1)
- x₂ − x₁ = 2 − 4 = −2
- y₂ − y₁ = −1 − 3 = −4
d = √[(−2)² + (−4)²] d = √(4 + 16) d = √20 d = √(4 × 5) d = 2√5
Answer: 2√5, which is option D.
Tip: When you get a square root, always check for a perfect-square factor (4, 9, 16, 25...). Here √20 = √4 × √5 = 2√5. Also, squaring removes negative signs, so don't worry about the order of subtraction.
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