WAEC 2014 Mathematics · Question 7

Make u the subject of formula, E = m2g\frac{m}{2g}(v2 - u2)

Options

  1. A.u = v2−2Egm\sqrt{v^2 - \frac{2Eg}{m}}
  2. B.u = v2m−2Eg4\sqrt{\frac{v^2}{m} - \frac{2Eg}{4}}
  3. C.u = v−2Egm\sqrt{v- \frac{2Eg}{m}}
  4. D.u = 2v2Egm\sqrt{\frac{2v^2Eg}{m}}

Answer: A. u = v2−2Egm\sqrt{v^2 - \frac{2Eg}{m}}

Explanation written with AI and checked against the answer key

Analyze the question: We need to rearrange E = (m/2g)(v² − u²) so that u stands alone on one side.

Concept: Use inverse operations in reverse order: undo the multiplication, then the subtraction, then the square.

Solution:

  1. Start with E = (m/2g)(v² − u²)
  1. Multiply both sides by 2g: 2gE = m(v² − u²)
  1. Divide both sides by m: 2gE/m = v² − u²
  1. Make u² the subject by moving it to the left and 2gE/m to the right: u² = v² − 2gE/m
  1. Take the square root of both sides: u = √(v² − 2Eg/m)

Checking the options:

  • A: √(v² − 2Eg/m). This matches our result exactly.
  • B: Has v²/m and 4 in the denominator, so it is wrong.
  • C: Has v instead of v², so it is wrong.
  • D: Has the wrong structure because it multiplies instead of subtracting, so it is wrong.

The correct answer is A.

Tip: In "change of subject" questions, remove the things attached to the variable in reverse order, as in BODMAS. Always remember to square root at the end, and check that v² keeps its square, as option C tries to trick you on this.

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.