WAEC 2014 Mathematics · Question 40
A ship sails x km due east to a point E and continues x km due north to F. Find the bearing the bearing of f from the starting point.
Options
- A.045o
- B.090o
- C.135o
- D.225o
Answer: A. 045o
Explanation written with AI and checked against the answer key
Analyze the question: A ship starts at a point (call it O), sails x km due east to E, then x km due north to F. We need the bearing of F from O.
Concept: A bearing is measured clockwise from North, written as three digits. For the bearing of F from O, we stand at O and measure the angle from the North line to the line OF.
Solution:
- Draw O at the origin. E is x km directly east of O. F is x km directly north of E.
- Triangle OEF has a right angle at E, with OE = EF = x. So it is an isosceles right triangle, and the angles at O and F are each 45°.
- Check with tan: the angle between OF and the East line is tan θ = EF/OE = x/x = 1, so θ = 45°.
- The bearing is measured from North. Since OF lies 45° north of East, it is 45° from East toward North. East is 090°, so the bearing is 090° − 45° = 045°.
So F is on a line at 45° clockwise from North, which is north-east of O.
Answer: 045°, which is option A.
Tip: When a ship goes equal distances east and north, the bearing is always 045° (north-east). Equal distances east and south give 135°. Equal distances west and south give 225°. Equal distances west and north give 315°. Always sketch a small diagram and measure clockwise from North.
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