WAEC 2013 Mathematics · Question 32
If x = 64 and y = 27, evaluate:
Options
- A.2
- B.1
- C.
- D.
Answer: C.
Explanation written with AI and checked against the answer key
Step 1: Analyze the question We substitute x = 64 and y = 27 into the expression and simplify, using the laws of indices.
Step 2: Concept
- x^(1/2) is the square root of x.
- y^(1/3) is the cube root of y.
- x^(2/3) = (cube root of x)², i.e. (∛x)².
Step 3: Solution
Numerator:
- x^(1/2) = 64^(1/2) = 8
- y^(1/3) = 27^(1/3) = 3
- Numerator = 8 − 3 = 5
Denominator:
- y = 27
- x^(2/3) = (64^(1/3))² = 4² = 16
- Denominator = 27 − 16 = 11
So the expression = 5/11.
Step 4: Answer
Tip: For fractional indices, take the root first (the denominator of the power), then raise to the power (the numerator). For example, 64^(2/3) = (∛64)² = 4² = 16. This keeps the numbers small and easy to handle without a calculator.
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