WAEC 2013 Mathematics · Question 18
Four oranges sell for Nx and three mangoes sell for Ny. Olu bought 24 oranges and 12 mangoes. How much did he pay in terms of x and y?
Options
- A.N94x + 6y)
- B.N(6x + 4y)
- C.N(24x + 12y)
- D.N(12x + 24y)
Answer: B. N(6x + 4y)
Explanation written with AI and checked against the answer key
Analyze the question: The prices are given for groups of items (4 oranges and 3 mangoes), not for single items. So we need to find how many groups Olu bought.
Concept: If a group of items costs a fixed amount, then Total cost = (number of groups) × (cost per group).
Solution:
- Oranges: 4 oranges cost Nx. Number of groups in 24 oranges = 24 ÷ 4 = 6 Cost = N6x
- Mangoes: 3 mangoes cost Ny. Number of groups in 12 mangoes = 12 ÷ 3 = 4 Cost = N4y
- Total cost = N(6x + 4y)
Check against the options:
- A. "N94x + 6y)" is a typo-looking option and does not match.
- B. N(6x + 4y) matches our working.
- C and D would be correct only if each orange cost x and each mango cost y, which is not what the question says.
Tip: When prices are given for a group (like "4 oranges for Nx"), always divide the quantity bought by the group size first. Don't multiply the quantity directly by x or y. Options like C and D are traps for students who skip this step.
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