WAEC 2013 Mathematics · Question 41
An open cone with base radius 28cm and perpendicular height 96cm was stretched to form sector of a circle…
Question
An open cone with base radius 28cm and perpendicular height 96cm was stretched to form sector of a circle. calculate the arc of the sector (Take )
- A.8800cm2
- B.8448cm2
- C.4400cm2
- D.4224cm2
Answer: A. 8800cm2
Explanation written with AI and checked against the answer key
Analyze the question: An open cone (curved surface only) is opened out flat into a sector. The question says "arc," but the options are in cm², so the intended quantity is almost certainly the area of the sector, which equals the curved surface area of the cone.
Concept:
- Slant height: l = √(r² + h²)
- Curved surface area of cone = πrl
- The sector's radius is l, and its arc length equals the base circumference 2πr.
Solution:
- Slant height: l = √(28² + 96²) = √(784 + 9216) = √10000 = 100 cm
- Curved surface area = area of sector: A = πrl = (22/7) × 28 × 100 = 22 × 4 × 100 = 8800 cm²
Check on "arc": The actual arc length would be 2πr = 2 × (22/7) × 28 = 176 cm, which is not among the options (and the options are in cm², not cm). So the question wording is faulty, and the answer that fits the options is the sector area, 8800 cm².
Option B (8448) would be π × 28 × 96, which wrongly uses the vertical height instead of the slant height. Option D (4224) is half of that. Option C (4400) is half of 8800, which comes from wrongly using ½πrl.
Answer: A. 8800 cm²
Tip: For cone problems, always find the slant height first. Look for Pythagorean triples: here 28:96:100 is 7:24:25 scaled by 4. Also, never use the vertical height in the curved surface area formula.
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