WAEC 2012 Mathematics · Question 16

Which of these statements about y = 8m\sqrt{8m} is correct?

Options

  1. A.log y = log 8 x log m\sqrt{m}
  2. B.log y = 3 log 2 x 12\frac{1}{2} log m
  3. C.log y = 3 log 2 - 12\frac{1}{2} log m
  4. D.log y = 32\frac{3}{2} log 2 + 12\frac{1}{2} log m

Answer: D. log y = 32\frac{3}{2} log 2 + 12\frac{1}{2} log m

Explanation written with AI and checked against the answer key

Analyze the question: We need to take logs of y = √(8m) and see which option matches.

Concept: Log laws:

  • log(ab) = log a + log b
  • log(aⁿ) = n log a
  • √x = x^(1/2)

Solution:

y = √(8m) = (8m)^(1/2)

Take logs of both sides:

log y = ½ log(8m)

log y = ½ (log 8 + log m)

Since 8 = 2³, log 8 = 3 log 2:

log y = ½ (3 log 2 + log m)

log y = (3/2) log 2 + ½ log m

Checking the options:

  • A: Uses multiplication of logs (log 8 × log √m). This is wrong, because the product rule gives addition.
  • B: Multiplies 3 log 2 by ½ log m. This is wrong for the same reason.
  • C: Subtracts ½ log m. This is wrong, because the terms are added.
  • D: (3/2) log 2 + ½ log m. This matches our result.

Tip: When you see a product inside a log, it becomes a sum. A square root means a power of ½, so multiply the whole log by ½. Always rewrite numbers like 8 as powers of 2 (8 = 2³) to simplify.

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