WAEC 2012 Mathematics · Question 47
Make p the subject of the relation: q =
Options
- A.p =
- B.p = 2qr - sr - 3
- C.p =
- D.p =
Answer: D. p =
Explanation written with AI and checked against the answer key
Analyze the question: We need to isolate p in q = 3p/r + s/2.
Concept: Use inverse operations. First move the term without p to the other side, then clear the fractions, then divide by the coefficient of p.
Solution:
- Start with: q = 3p/r + s/2
- Subtract s/2 from both sides: q − s/2 = 3p/r
- Combine the left side over a common denominator: (2q − s)/2 = 3p/r
- Cross-multiply: r(2q − s) = 6p
- Divide by 6: p = r(2q − s)/6 = (2qr − rs)/6
Check against the options:
- A: (2q − rs)/6 is wrong because r was not multiplied through the q term.
- B: wrong form entirely.
- C: (2qr − s)/6 is wrong because r was not multiplied through the s term.
- D: (2qr − rs)/6 matches our result.
Tip: When you clear fractions, multiply every term by the denominator. Here r multiplies both 2q and s. A quick check is to substitute simple numbers, such as p = 2, r = 1, s = 2. Then q = 6 + 1 = 7, and option D gives (14 − 2)/6 = 2, which is correct.
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