WAEC 2012 Mathematics · Question 2
Express 302.10495 correct to five significant figures
Options
- A.302.10
- B.302.11
- C.302.105
- D.302.1049
Answer: A. 302.10
Explanation written with AI and checked against the answer key
Analyze the question: We need to round 302.10495 to 5 significant figures.
Concept: Significant figures count from the first non-zero digit, and zeros between non-zero digits count too. To round, look at the digit right after the last digit you keep. If it is 5 or more, round up. If it is less than 5, leave the last kept digit unchanged.
Solution:
Digits of 302.10495, counted from the left:
- 3
- 0
- 2
- 1
- 0
- 4
- 9
- 5
The first 5 significant figures are 3, 0, 2, 1, 0, which gives 302.10.
The next digit (the 6th significant figure) is 4. Since 4 is less than 5, we do not round up. The 9 and 5 that follow do not matter. Rounding is decided only by the digit immediately after the cut-off. Rounding in steps (0.10495 → 0.1050 → 0.105) is a common mistake and gives a wrong result.
So 302.10495 ≈ 302.10 (5 s.f.)
Check the other options:
- B (302.11) is what you get by wrongly rounding in steps, or by treating it as 4 s.f.
- C (302.105) has 6 significant figures.
- D (302.1049) has 7 significant figures.
Only A has exactly 5 significant figures and is correctly rounded.
Tip: Never round in stages. Find the cut-off point, look only at the very next digit, and decide once. Also remember that the trailing zero in 302.10 must be kept, because it is a significant figure.
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