WAEC 2011 Mathematics · Question 27
Esther was facing S 20° W. She turned 90° in the clock wise direction. What direction is she facing?
Options
- A.N 70o W
- B.S 70o W
- C.N 20o W
- D.S 20o E
Answer: A. N 70o W
Explanation written with AI and checked against the answer key
Analyze the question: Esther starts facing S 20° W, meaning she faces south, then rotated 20° towards the west. She then turns 90° clockwise. We need her new direction.
Concept: Bearings in the form "S θ W" are measured from the South line towards the West. Clockwise turning, viewed from above, goes N → E → S → W → N.
Step-by-step:
- Convert S 20° W to a full-circle bearing (measured clockwise from North): • South = 180° • Moving 20° towards West from South means going further clockwise (S → W is clockwise) • So the bearing = 180° + 20° = 200°
- Turn 90° clockwise: • 200° + 90° = 290°
- Convert 290° back to a quadrant bearing: • 290° lies between 270° (West) and 360° (North), so it is in the North-West quadrant. • Angle from North towards West = 360° − 290° = 70° • So the direction is N 70° W.
Check: 290° is 20° past West (270°) towards North. Measured from North, that is 70° towards the West. Both agree: N 70° W.
Answer: A. N 70° W
Tip: Convert quadrant bearings to three-figure bearings (0°–360°) first, add the clockwise turn (or subtract for anticlockwise), then convert back. This avoids sketching mistakes.
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