WAEC 2010 Mathematics · Question 28

Simplify 22+x+22−x\frac{2}{2 + x} + \frac{2}{2 - x}

Options

  1. A.44−x3\frac{4}{4 - x^3}
  2. B.84−x2\frac{8}{4 - x^2}
  3. C.4x4−x2\frac{4x}{4 - x^2}
  4. D.8−4x4−x2\frac{8 - 4x}{4 - x^2}

Answer: B. 84−x2\frac{8}{4 - x^2}

Explanation written with AI and checked against the answer key

Analyze the question: We need to add two algebraic fractions with different denominators, so we must find a common denominator first.

Concept: To add fractions, use the common denominator. Here the denominators are (2 + x) and (2 − x), and their product is a difference of two squares:

(2 + x)(2 − x) = 4 − x²

Solution:

22+x+22−x=2(2−x)+2(2+x)(2+x)(2−x)\frac{2}{2+x} + \frac{2}{2-x} = \frac{2(2-x) + 2(2+x)}{(2+x)(2-x)}

Expand the numerator:

2(2 − x) = 4 − 2x 2(2 + x) = 4 + 2x

Add them: (4 − 2x) + (4 + 2x) = 8 (the x terms cancel)

So:

22+x+22−x=84−x2\frac{2}{2+x} + \frac{2}{2-x} = \frac{8}{4 - x^2}

Check with a number: Let x = 1. The left side is 2/3 + 2/1 = 8/3. Option B gives 8/(4 − 1) = 8/3 ✓. (Option C would give 4/3, which is wrong.)

Tip: When the denominators are (a + b) and (a − b), the common denominator is a² − b². Also, watch for terms like −2x and +2x that cancel in the numerator. A quick substitution check, such as x = 1, can confirm your answer in seconds during the exam.

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