WAEC 2010 Mathematics · Question 33

If y = (2x2+m)3N\frac{(2\sqrt{x^2 + m})}{3N}, make x the subject of the formular

Options

  1. A.9y2N2−2m3\frac{\sqrt{9y^2 N^2 - 2m}}{3}
  2. B.9y2N2−4m2\frac{\sqrt{9y^2 N^2 - 4m}}{2}
  3. C.9y2N2−3m2\frac{\sqrt{9y^2 N^2 - 3m}}{2}
  4. D.9y2N−3m2\frac{\sqrt{9y^2 N - 3m}}{2}

Answer: B. 9y2N2−4m2\frac{\sqrt{9y^2 N^2 - 4m}}{2}

Explanation written with AI and checked against the answer key

Analyze the question: We need to make x the subject of y = 2√(x² + m) / (3N).

Concept: To free x from a square root, isolate the root, square both sides, then solve for x².

Solution:

  1. Multiply both sides by 3N: 3Ny = 2√(x² + m)
  1. Divide by 2: √(x² + m) = 3Ny/2
  1. Square both sides: x² + m = 9N²y²/4
  1. Make x² the subject: x² = 9N²y²/4 − m = (9N²y² − 4m)/4
  1. Take the square root: x = √(9y²N² − 4m) / 2

Matching the options: This is exactly option B.

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Tip: When you see a square root in a "change of subject" question, follow this order: isolate the root, square both sides, then solve. Remember to square the whole side, including the denominator: (3Ny/2)² = 9N²y²/4, not 9N²y²/2.

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