WAEC 2010 Mathematics · Question 20

c c No. of pets 0 1 2 3 4 No. of students 8 4 5 10 3 The table shows the number of pets kept by 30 students in…

Question

No. of pets01234No. of students845103\begin{array}{c|c} \text{No. of pets} & 0 & 1 & 2 & 3 & 4 \\ \hline \text{No. of students} & 8 & 4 & 5 & 10 & 3\end{array} The table shows the number of pets kept by 30 students in a class. If a student is picked at random ftom the class. What is the probability that he/she kept more than one pet?

  1. A.15\frac{1}{5}
  2. B.25\frac{2}{5}
  3. C.35\frac{3}{5}
  4. D.45\frac{4}{5}

Answer: C. 35\frac{3}{5}

Explanation written with AI and checked against the answer key

Analyze the question: We need the probability that a randomly chosen student kept more than one pet, meaning 2, 3, or 4 pets.

Concept: Probability = (number of favourable outcomes) / (total number of outcomes).

Solution:

Students with more than one pet:

  • 2 pets: 5 students
  • 3 pets: 10 students
  • 4 pets: 3 students

Favourable = 5 + 10 + 3 = 18

Check the total: 8 + 4 + 5 + 10 + 3 = 30 ✓ (matches the 30 students stated)

P(more than one pet) = 18/30 = 3/5

Answer: C. 3/5

Tip: "More than one" does not include 1. Watch for wording such as "at least", "more than", and "at most", since they change which values you count. You can also use the complement as a check: students with 0 or 1 pet = 8 + 4 = 12, so 1 − 12/30 = 18/30 = 3/5 ✓.

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