The volume of 22g of CO$_2$ at stp is equivalent to [C =12, O =16, molar volume at stp = 22.4 dm$^3$ ]

Analyze the question: We need the volume occupied by 22 g of CO₂ at STP, using the molar volume of 22.4 dm³.

Concept: One mole of any gas occupies 22.4 dm³ at STP.

moles = mass ÷ molar mass, and volume at STP = moles × 22.4 dm³

Solution:

1. Molar mass of CO₂ = 12 + (2 × 16) = 44 g/mol
2. Moles of CO₂ = 22 ÷ 44 = 0.5 mol
3. Volume = 0.5 × 22.4 = 11.2 dm³

Answer: The volume is 11.2 dm³, which is option C.

Tip: Check how 22 g compares with the molar mass. Here 22 g is exactly half of 44 g, so the volume is half of 22.4 dm³. Spotting simple fractions like this saves time in the exam.