WAEC 2024 Chemistry · Question 35

Consider the reaction represented by the equation: C 3 H 8 + 5 O 2 → 3CO 2 + 4H 2 O If 0.1 mole of C 3 H 8 was…

Question

Consider the reaction represented by the equation:    C3_3H8_8  +  5 O2_2  → 3CO2_2  +  4H2_2O If 0.1 mole of  C3_3H8_8 was completely burnt, what volume of CO2_2 would be produced at stp? [volume of gas at stp = 22.4dm3^3mol−1^{-1}].

  1. A.6.72dm3^3
  2. B.2.24dm3^3
  3. C.0.30 dm3^3
  4. D.0.10dm3^3

Answer: A. 6.72dm3^3

Explanation written with AI and checked against the answer key

Step 1: Analyze the question We are given 0.1 mole of propane (C₃H₈) burnt completely. We need the volume of CO₂ produced at stp. Step 2: Concept The balanced equation gives mole ratios. At stp, 1 mole of any gas occupies 22.4 dm³: Volume = moles × 22.4 dm³/mol Step 3: Solution From the equation: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O 1 mole of C₃H₈ produces 3 moles of CO₂. So 0.1 mole of C₃H₈ produces: 0.1 × 3 = 0.3 mole of CO₂ Volume of CO₂ = 0.3 × 22.4 = 6.72 dm³ Step 4: Answer The correct option is A. 6.72 dm³. Note that option C (0.30 dm³) is a trap. It is the number of moles of CO₂, not the volume. Always multiply by 22.4 to convert moles to volume. Tip: For gas-volume questions, follow this chain: moles given → mole ratio from the equation → moles wanted → × 22.4 dm³. Check that your final answer is in volume units, not moles.

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