DeeepSolve Logo
DeeepSolve
Get app

WAEC 2023 Chemistry · Question 24

Determine the volume of 0.100 mol of HCl in 0.250moldm30.250 mol dm^3 of solution.

Options

  1. A.200cm3200cm^3
  2. B.100cm3100cm^3
  3. C.20cm320cm^3
  4. D.400cm3400cm^3

Answer: D. 400cm3400cm^3

Explanation written with AI and checked against the answer key

Analyze the question: We have 0.100 mol of HCl, and the concentration of the solution is 0.250 mol/dm³. We need the volume of solution that contains this amount of HCl. Concept: Concentration (molarity) is moles of solute per unit volume of solution: C = n / V, so V = n / C Solution: V = 0.100 mol ÷ 0.250 mol/dm³ V = 0.4 dm³ Convert to cm³ (1 dm³ = 1000 cm³): V = 0.4 × 1000 = 400 cm³ Answer: Option D, 400 cm³. Tip: Always check the units. Mole ÷ (mol/dm³) gives dm³, and you must multiply by 1000 to get cm³. A quick check: 0.250 mol/dm³ is a quarter of a mole per dm³, so you need 4 dm³ for 1 mol, and therefore 0.4 dm³ for 0.1 mol.

AI can make mistakes. Report anything that looks wrong.

Practise similar questionsGet step-by-step help on DeeepSolve

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.