WAEC 2019 Chemistry · Question 15

Consider the following reaction represented by the following equation: C2_2H2_2 →H2^{H_2}_{→} X  →H2^{H_2}_{→} Y.           X and Y respectively are?

Options

  1. A.ethane and ethene
  2. B.ethene and ethane
  3. C.ethyne and ethene
  4. D.ethane and ethyne

Answer: B. ethene and ethane

Explanation written with AI and checked against the answer key

Analyze the question: Ethyne (C₂H₂) reacts with hydrogen in two stages. We need to identify the product after each stage.

Concept: This is catalytic hydrogenation, which is an addition reaction. Each mole of H₂ added reduces the degree of unsaturation by one bond:

  • Alkyne (triple bond) → alkene (double bond) → alkane (single bond)

Solution:

Step 1: Ethyne adds one mole of H₂ (catalyst such as Ni or Pd), and the triple bond becomes a double bond:

C₂H₂ + H₂ → C₂H₄ (X = ethene)

Step 2: Ethene adds another mole of H₂ (Ni catalyst, about 200°C), and the double bond becomes a single bond:

C₂H₄ + H₂ → C₂H₆ (Y = ethane)

So X = ethene and Y = ethane.

Checking the options:

  • A. Reversed order, so wrong.
  • B. Ethene and ethane, which is correct.
  • C. Ethyne is the starting material, so it can't be a product.
  • D. Ethane can't come first, and ethyne can't be a product of hydrogenation.

Tip: Remember the sequence of hydrogenation as -yne → -ene → -ane. Each H₂ added takes you one step down the series: ethyne → ethene → ethane. Adding hydrogen always means moving toward more saturated.

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