WAEC 2019 Chemistry · Question 15
Consider the following reaction represented by the following equation: CH X Y. X and Y respectively are?
Options
- A.ethane and ethene
- B.ethene and ethane
- C.ethyne and ethene
- D.ethane and ethyne
Answer: B. ethene and ethane
Explanation written with AI and checked against the answer key
Analyze the question: Ethyne (C₂H₂) reacts with hydrogen in two stages. We need to identify the product after each stage.
Concept: This is catalytic hydrogenation, which is an addition reaction. Each mole of H₂ added reduces the degree of unsaturation by one bond:
- Alkyne (triple bond) → alkene (double bond) → alkane (single bond)
Solution:
Step 1: Ethyne adds one mole of H₂ (catalyst such as Ni or Pd), and the triple bond becomes a double bond:
C₂H₂ + H₂ → C₂H₄ (X = ethene)
Step 2: Ethene adds another mole of H₂ (Ni catalyst, about 200°C), and the double bond becomes a single bond:
C₂H₄ + H₂ → C₂H₆ (Y = ethane)
So X = ethene and Y = ethane.
Checking the options:
- A. Reversed order, so wrong.
- B. Ethene and ethane, which is correct.
- C. Ethyne is the starting material, so it can't be a product.
- D. Ethane can't come first, and ethyne can't be a product of hydrogenation.
Tip: Remember the sequence of hydrogenation as -yne → -ene → -ane. Each H₂ added takes you one step down the series: ethyne → ethene → ethane. Adding hydrogen always means moving toward more saturated.
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