WAEC 2011 Chemistry · Question 16
Which of the following compounds would react with ethanoic acid to give a sweet smelling liquid?
Options
- A.Alkane
- B.Alkanol
- C.Alkanal
- D.Alkyne
Answer: B. Alkanol
Explanation written with AI and checked against the answer key
Analyze the question: A sweet-smelling (fruity) liquid is the typical description of an ester. So we need to find which compound reacts with ethanoic acid to form an ester.
Concept: Esterification is the reaction between a carboxylic acid and an alcohol (alkanol) in the presence of concentrated H₂SO₄ as catalyst, producing an ester and water.
General equation:
RCOOH + R'OH ⇌ RCOOR' + H₂O
Example with ethanoic acid and ethanol:
CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O (conc. H₂SO₄, heat)
The product, ethyl ethanoate, has a sweet, fruity smell.
Checking the options:
- A. Alkane: Saturated hydrocarbons are unreactive toward carboxylic acids. No reaction.
- B. Alkanol: Reacts with ethanoic acid to form an ester. Correct.
- C. Alkanal: Aldehydes do not form esters with carboxylic acids.
- D. Alkyne: Unsaturated hydrocarbons undergo addition reactions, and they do not form esters with ethanoic acid under normal conditions.
Exam tip: Remember "Acid + Alcohol → Ester + Water." Whenever you see "sweet smell" or "fruity smell" in a question, think ester, and look for the alkanol (alcohol) option.
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