WAEC 2011 Chemistry · Question 26
Which of the following arrangements is in order of increasing metallic property?
Options
- A.Li < Na< k
- B.Na < Li < K
- C.K
- D.K < Li < Na
Answer: A. Li < Na< k
Explanation written with AI and checked against the answer key
Analyze the question: We need the order of increasing metallic property for the alkali metals Li, Na and K. Option C is incomplete ("K"), so we focus on the other options.
Concept: Metallic character depends on how easily an atom loses its outer electron(s) to form a positive ion.
- Going down a group, atomic radius increases.
- The outer electron is farther from the nucleus and is more shielded by inner electrons.
- So it is lost more easily, and metallic character increases down the group.
Solution: Group 1 order from top to bottom: Li (period 2), Na (period 3), K (period 4).
- Li has the smallest atomic size and holds its outer electron most tightly, so it is the least metallic.
- Na is in between.
- K has the largest size and loses its outer electron most easily, so it is the most metallic.
Increasing metallic property: Li < Na < K
Checking the options:
- A. Li < Na < K ✔ matches
- B. Na < Li < K ✘ (Li should come first)
- C. "K" ✘ (incomplete, not a valid arrangement)
- D. K < Li < Na ✘ (K is the most metallic, not the least)
Tip: For metals, reactivity and metallic character increase down a group and decrease across a period (left to right). Remember the alkali metals' reactivity with water: Li is gentle, Na is vigorous, K is violent (burns with a lilac flame). The more violent the reaction, the more metallic the element.
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