NECO 2002 Physics · Question 36
The wavelength of a stationary wave is 36.0cm. What is the distance between a node and the next anti-node?
Options
- A.6.0cm
- B.9.0cm
- C.18.0cm
- D.360cm
- E.72.0cm
Answer: B. 9.0cm
Explanation written with AI and checked against the answer key
Analyze the question: We're given the wavelength of a stationary (standing) wave and asked for the distance between a node and the next adjacent anti-node.
Concept: In a stationary wave:
- Distance between two successive nodes = λ/2
- Distance between two successive anti-nodes = λ/2
- Distance between a node and the next anti-node = λ/4
This is because a node and an anti-node sit half of a half-wavelength apart. Going from node to anti-node to node covers λ/2, so each step is λ/4.
Solution:
Distance = λ/4
= 36.0 cm ÷ 4
= 9.0 cm
Answer: B (9.0 cm)
Tip: Remember the pattern "N to N = λ/2, N to A = λ/4." Option C (18.0 cm) is the trap: it is the distance between two successive nodes (λ/2), so check whether the question asks for node-to-node or node-to-anti-node.
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