NECO 2000 Physics · Question 3
An element of nuclear number A and proton number Z emits an alpha particle from its nucleus. The nucleon…
Question
An element of nuclear number A and proton number Z emits an alpha particle from its nucleus. The nucleon number and the proton number of the new element formed are respectively
- A.(A – 2) and (Z – 2)
- B.(A + 4) and (Z + 2)
- C.(A– 4) and (Z+2)
- D.(A+ 4) and (Z – 2)
- E.(A – 4) and (Z – 2)
Answer: E. (A – 4) and (Z – 2)
Explanation written with AI and checked against the answer key
Analyze the question: An alpha particle is emitted from a nucleus. We need the new nucleon number (mass number) and proton number (atomic number). The question says "nuclear number A", which here means nucleon (mass) number.
Concept: An alpha particle is a helium nucleus, ⁴₂He. It contains 2 protons and 2 neutrons, so it has a mass number of 4 and a proton number of 2.
When a nucleus emits an alpha particle, it loses both of these:
ᴬZ X → ᴬ⁻⁴(Z−2) Y + ⁴₂He
Step by step:
- Nucleon number: A − 4 (the alpha particle carries away 4 nucleons)
- Proton number: Z − 2 (the alpha particle carries away 2 protons)
Example: Uranium-238 (Z = 92) emits an alpha particle and becomes Thorium-234 (Z = 90). Here 238 − 4 = 234 and 92 − 2 = 90.
Answer: The new element has nucleon number (A − 4) and proton number (Z − 2), which is option E.
Tip: Remember that alpha decay reduces the mass number by 4 and the atomic number by 2. Beta decay is different. It leaves the mass number unchanged and increases the atomic number by 1. Options with "+" are never correct for alpha emission, because the nucleus only loses particles.
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