NECO 2008 Mathematics · Question 33

If tan α = 12\frac{1}{2} and tan β = 13\frac{1}{3} and both α and β are acute, find tan (α + β).

Options

  1. A.0.015
  2. B.1
  3. C.10
  4. D.39.81
  5. E.45

Answer: B. 1

Explanation written with AI and checked against the answer key

Analyze the question: You are given tan α and tan β and asked for tan (α + β). This calls for the tangent addition formula.

Concept:

tan(α + β) = (tan α + tan β) / (1 − tan α · tan β)

Solution:

  1. Numerator: 1/2 + 1/3 = 3/6 + 2/6 = 5/6
  2. Denominator: 1 − (1/2)(1/3) = 1 − 1/6 = 5/6
  3. Divide: tan(α + β) = (5/6) ÷ (5/6) = 1

Since tan(α + β) = 1, α + β = 45°, which makes sense because both angles are acute and fairly small (about 26.6° and 18.4°, which add up to 45°).

Answer: B (1)

Tip: Note that option E (45) is the angle, not the tangent value. Examiners include this kind of trap, so always check whether the question asks for the ratio or the angle. Also remember the sign pattern: the numerator has a plus, and the denominator has a minus, for tan(α + β).

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