NECO 2008 Mathematics · Question 33
If tan α = and tan β = and both α and β are acute, find tan (α + β).
Options
- A.0.015
- B.1
- C.10
- D.39.81
- E.45
Answer: B. 1
Explanation written with AI and checked against the answer key
Analyze the question: You are given tan α and tan β and asked for tan (α + β). This calls for the tangent addition formula.
Concept:
tan(α + β) = (tan α + tan β) / (1 − tan α · tan β)
Solution:
- Numerator: 1/2 + 1/3 = 3/6 + 2/6 = 5/6
- Denominator: 1 − (1/2)(1/3) = 1 − 1/6 = 5/6
- Divide: tan(α + β) = (5/6) ÷ (5/6) = 1
Since tan(α + β) = 1, α + β = 45°, which makes sense because both angles are acute and fairly small (about 26.6° and 18.4°, which add up to 45°).
Answer: B (1)
Tip: Note that option E (45) is the angle, not the tangent value. Examiners include this kind of trap, so always check whether the question asks for the ratio or the angle. Also remember the sign pattern: the numerator has a plus, and the denominator has a minus, for tan(α + β).
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