NECO 2008 Mathematics · Question 10

2 bags of sugar at Nx per bag are mixed with 3 bags of sugar at Ny per bag. What is the cost in N of the mixture per bag?

Options

  1. A.(2x+3y)5\frac{(2x + 3y)}{5}
  2. B.(x+y)2\frac{(x + y)}{2}
  3. C.x2+y3\frac{x}{2} +\frac{y}{3}
  4. D.(x+y)5\frac{(x + y)}{5}
  5. E.(3x+2y)5\frac{(3x + 2y)}{5}

Answer: A. (2x+3y)5\frac{(2x + 3y)}{5}

Explanation written with AI and checked against the answer key

Analyze the question: Two lots of sugar with different prices per bag are mixed. We need the cost per bag of the mixture, which is the average cost.

Concept: Cost per bag of a mixture = (total cost of all bags) ÷ (total number of bags)

Solution:

  • 2 bags at Nx each: cost = 2x
  • 3 bags at Ny each: cost = 3y
  • Total cost = 2x + 3y
  • Total number of bags = 2 + 3 = 5

Cost per bag of the mixture:

2x+3y5\frac{2x + 3y}{5}

Checking the options:

  • A. (2x + 3y)/5 matches our result.
  • B. (x + y)/2 ignores the number of bags of each type.
  • C. x/2 + y/3 divides the prices by the numbers of bags, which is wrong.
  • D. (x + y)/5 does not multiply each price by its number of bags.
  • E. (3x + 2y)/5 swaps the quantities (it would be correct for 3 bags at x and 2 bags at y).

Tip: For mixture questions, always weight each price by its quantity: (quantity₁ × price₁ + quantity₂ × price₂) ÷ total quantity. Make sure each quantity multiplies its own price, because option E is a common trap that swaps them.

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