NECO 2002 Mathematics · Question 32
One bag contains 4 white balls and 2 black balls. Another bag contains 3 white balls and 5 black balls, if one…
Question
One bag contains 4 white balls and 2 black balls. Another bag contains 3 white balls and 5 black balls, if one ball is drawn from each bag, what is the probability that both are white?
- A.
- B.
- C.
- D.
- E.
Answer: D.
Explanation written with AI and checked against the answer key
Analyze the question: Two bags, one ball drawn from each. We need P(both white). The draws are independent, so we multiply the probabilities.
Concept: For independent events, P(A and B) = P(A) × P(B).
Solution:
- Bag 1: 4 white + 2 black = 6 balls, so P(white) = 4/6 = 2/3
- Bag 2: 3 white + 5 black = 8 balls, so P(white) = 3/8
P(both white) = 2/3 × 3/8 = 6/24 = 1/4
Tip: When the question says "one from each bag," the events are independent, so multiply. Always simplify fractions before choosing an option. Here 6/24 reduces to 1/4. Also, cancel across the fractions early (the 3s cancel) to save time: 2/3 × 3/8 = 2/8 = 1/4.
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