NECO 2002 Mathematics · Question 32

One bag contains 4 white balls and 2 black balls. Another bag contains 3 white balls and 5 black balls, if one…

Question

One bag contains 4 white balls and 2 black balls. Another bag contains 3 white balls and 5 black balls, if one ball is drawn from each bag, what is the probability that both are white?

  1. A.23\frac{2}{3}
  2. B.38\frac{3}{8}
  3. C.724\frac{7}{24}
  4. D.14\frac{1}{4}
  5. E.124\frac{1}{24}

Answer: D. 14\frac{1}{4}

Explanation written with AI and checked against the answer key

Analyze the question: Two bags, one ball drawn from each. We need P(both white). The draws are independent, so we multiply the probabilities.

Concept: For independent events, P(A and B) = P(A) × P(B).

Solution:

  • Bag 1: 4 white + 2 black = 6 balls, so P(white) = 4/6 = 2/3
  • Bag 2: 3 white + 5 black = 8 balls, so P(white) = 3/8

P(both white) = 2/3 × 3/8 = 6/24 = 1/4

Tip: When the question says "one from each bag," the events are independent, so multiply. Always simplify fractions before choosing an option. Here 6/24 reduces to 1/4. Also, cancel across the fractions early (the 3s cancel) to save time: 2/3 × 3/8 = 2/8 = 1/4.

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