NECO 2001 Mathematics · Question 25

If s = (a2x2−b2y2)\sqrt{(\frac{a^2}{x^2} - \frac{b^2}{y^2})}what does y equal?

Options

  1. A.(b2−a2)(s2−x2)\sqrt{\frac{(b^2 - a^2)}{(s^2 - x^2)}}
  2. B.(b2−a2)(s2×2)\sqrt{\frac{(b^2 - a^2)}{(s^2 \times 2)}}
  3. C.x2−a2−b2s\sqrt{\frac{x^2 - a^2 - b^2}{s}}
  4. D.x2−a2−b2s\frac{x^2 - a^2 - b^2}{s}
  5. E.(b2x2)(a2−s2x2)\sqrt{\frac{(b^2 x^2)}{(a^2 - s^2 x^2)}}

Answer: E. (b2x2)(a2−s2x2)\sqrt{\frac{(b^2 x^2)}{(a^2 - s^2 x^2)}}

Explanation written with AI and checked against the answer key

Analyze the question: We need to make y the subject of s = √(a²/x² − b²/y²).

Step 1: Square both sides

s² = a²/x² − b²/y²

Step 2: Isolate the y term

b²/y² = a²/x² − s²

Step 3: Combine the right side into one fraction

b²/y² = (a² − s²x²)/x²

Step 4: Invert both sides and solve for y²

y²/b² = x²/(a² − s²x²)

y² = b²x²/(a² − s²x²)

Step 5: Take the square root

y = √[ b²x² / (a² − s²x²) ]

Compare with the options:

  • A, B, C and D do not match. They are missing the b²x² numerator and the a² − s²x² denominator.
  • E: √[(b²x²)/(a² − s²x²)] matches our result exactly.

Tip: In "change of subject" questions, follow this order:

  1. Remove the square root by squaring.
  2. Collect the term containing the required variable on one side.
  3. Combine fractions with a common denominator.
  4. Invert and take the root last.

Always check that your final expression has the same structure as the options. Here the b²x² on top and the a² − s²x² below are the giveaway.

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